Write a C program to convert decimal to binary and count the number of ones and zeros.
int main() {
int data, res = 0, i = 1;
int temp, mod, zeros = 0, ones = 0;
/* get the input from the user */
printf("Enter your input:");
scanf("%d", &data);
/* convert decimal to binary format */
while (data > 0) {
mod = data % 2;
res = res + (i * mod);
data = data / 2;
i = i * 10;
}
/* print the resultant binary value */
printf("Binary Value: %d\n", res);
temp = res;
/* calculate number of 0's and 1's in binary output */
while (res > 0) {
mod = res % 10;
if (!mod) {
zeros++;
} else {
ones++;
}
res = res / 10;
}
printf("\nNumber of zeros in %d is %d\n", temp, zeros);
printf("Number of ones in %d is %d\n", temp, ones);
return 0;
}
Output:
jp@jp-VirtualBox:~/$ ./a.out
Enter your input:121
Binary Value: 1111001
Number of zeros in 1111001 is 2
Number of ones in 1111001 is 5
Enter your input:121
Binary Value: 1111001
Number of zeros in 1111001 is 2
Number of ones in 1111001 is 5
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