Write a C program to find the sum of cubes of first n natural numbers.
int main() {
int num, cube, sum = 0, i = 1;
/* get the input value n from user */
printf("Enter the value for n:");
scanf("%d", &num);
/* calculate the sum of cubes of 1st n natural nos */
while (i <= num) {
cube = i * i * i;
sum = sum + cube;
i++;
}
/* print the sum of cubes of 1st n natural nos */
printf("Sum of cubes of first %d natural"
" numbers is %d\n", num, sum);
return 0;
}
Output:
jp@jp-VirtualBox:~/$ ./a.out
Enter the value for n:3
Sum of cubes of first 3 natural numbers is 36
Enter the value for n:3
Sum of cubes of first 3 natural numbers is 36
do you want to know how above program works
ReplyDeleteWhat is cube sum program written in c ?
In this cube sum program , we find cube of individual digit of a number and find their sum .for example: 123 = 1^3 + 2 ^3 + 3^3.
Cube of individual digit have to be found for that we have to extract each digit .As we know last digit of number can be extract using modulus division (i.e 123%10 = 3 ) , And if we do integer division of given number by 10 , we can get other digit excluding last digit .
http://onlineclab.blogspot.com/2016/02/cube-sum-program-c.html
I want it's flowchart
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