C program to find addition, subtraction, multiplication and division of two complex numbers

Write a C program to find addition, subtraction, multiplication and division of two complex numbers.

  #include <stdio.h>

  /* mutiply two complex numbers */
  void multiplyComplex(int num1[2], int num2[2], int num3[2]) {
        num3[0] = (num1[0] * num2[0]) + (-1 * num1[1] * num2[1]);
        num3[1] = (num1[1] * num2[0]) + (num1[0] * num2[1]);
        return;
  }

  /* division of two complex numbers */
  void divideComplex(int num1[2], int num2[2]) {
        int val1[2], val2[2];
        val1[0] = num2[0];
        val1[1] = -1 * num2[1];
        printf("Division Result:\n");
        multiplyComplex(num1, val1, val2);
        printf("(%d + (%di)) / ", val2[0], val2[1]);
        multiplyComplex(num1, val1, val2);
        printf("(%d + (%di))\n", val2[0], val2[1]);
        return;
  }

  int main() {
        int complex1[2], complex2[2], complex3[3], ch;

        /* get the first complex number from the user */
        printf("x+iy - First Complex number :");
        scanf("%d%d", &complex1[0], &complex1[1]);

        /* get the second complex number from the user */
        printf("x+iy - Second complex number:");
        scanf("%d%d", &complex2[0], &complex2[1]);

        /* provide option for different operations */
        printf("1. Addition\n2. Subtraction\n");
        printf("3. Multiplication\n4. Division\n");
        printf("Enter your choice:");

        scanf("%d", &ch);

        switch (ch) {

                case 1:

                        /* Add complex numbers */

                        complex3[0] = complex1[0] + complex2[0];

                        complex3[1] = complex1[1] + complex2[1];

                        printf("Addition Result:\n");

                        printf("%d + (%di)\n", complex3[0], complex3[1]);

                        break;

                case 2:

                        /* subtract complex numbers */

                        complex3[0] = complex1[0] - complex2[0];

                        complex3[1] = complex1[1] - complex2[1];

                        printf("Subtraction Result:\n");

                        printf("%d + (%di)\n", complex3[0], complex3[1]);

                        break;

                case 3:

                        /* multiply complex numbers */

                        multiplyComplex(complex1, complex2, complex3);

                        printf("Multiplication Result:\n");

                        printf("%d + (%di)\n", complex3[0], complex3[1]);

                        break;

                case 4:

                        /* divide complex numbers */

                        divideComplex(complex1, complex2);

                        break;

                default:

                        printf("Wrong option!!\n");

                        break;

        }

        return 0;

  }

  Output:

  jp@jp-VirtualBox:~/$ ./a.out
  x+iy - First Complex number :10 20
  x+iy - Second complex number:30 40
  1. Addition
  2. Subtraction
  3. Multiplication
  4. Division
  Enter your choice:1
  Addition Result:
  40 + (60i)