C program to find the size of the given array without using sizeof operator

C program to calculate the size of the given array without using sizeof operator.

  #include <stdio.h>
  #define MAXLIMIT 256

  int main() {
        int array[MAXLIMIT], size, val1, val2;

        /* get the address of first and second element */
        val1 = (int)&array[0];
        val2 = (int)&array[1];

        /* diff b/w the address gives the size of one element in the array */
        size = val2 - val1;

        /* printing the size of an element in the i/p array */
        printf("Size of an element in the given array is %d\n", size);

        /* printing the address of 1st and second element in i/p array */
        printf("&array[0]=>%x \n&array[1]=>%x\n",
                        (int)&array[0], (int)&array[1]);

        /* printing the address difference */
        printf("&array[1] - &array[0] => %d\n", size);

        /* calculating the given array size */
        size = (size * MAXLIMIT);

        /* printing the result */
        printf("\nSize of the given array is %d\n", size);
        return 0;
  }

  Output:

  jp@jp-VirtualBox:~/$ ./a.out
  Size of an element in the given array is 4
  &array[0]=>bfda587
  &array[1]=>bfda5878
  &array[1] - &array[0] => 4
  
  Size of the given array is 1024